The _printf() function takes one argument:
A string with / without specifiers to print and gives the output formatted.
The string is printed character by character and when founds a '%' with a letter calls one of that parameters and print them instead the specifiers.
Like the according main.h library version:
int _printf(const char *format, ...);Format generators are a format with which we tell the function to take the arguments according to the indicated type.
A format specifier follows this prototype: %type
The following format specifiers are supported:
| Type | Output |
|---|---|
| c | Print a character passed as parameter |
| s | Prints a string |
| % | Print a percentage symbol |
| d | Prints a signed decimal number |
| i | Prints a signed number (int) |
| b | Converts the unsigned integer to binary and prints it |
| r | Print the inverted string |
| R | Use ROT13 to converts the letters with the thirteenth letter forward of the alphabet. |
| Type | Output |
|---|---|
| u | Prints an unsigned decimal number |
| o | Prints the octal unsigned integer conversion |
| x | Unsigned hex conversion to lowercase |
| X | Unsigned hex conversion to uppercase |
| p | Print a memory address(pointer) |
- %b : The specifier %b doesn't work all correctly
#include "main.h"
int main (void)
{
_printf ("I am a character %s", 'F');
return (0);
}Output : I am a character F
#include "main.h"
int main (void)
{
_printf ("%s", "STRING");
return (0);
}Output : STRING
#include "main.h"
int main (void)
{
_printf ("I am percentage %%");
return (0);
}Output : I am a percentage %
#include "main.h"
int main (void)
{
_printf ("I am an integer %i", 10);
return (0);
}Output : I am an integer 10
#include "main.h"
int main (void)
{
_printf ("I am a binary %b", 54);
return (0);
}Output : I am a binary 110110
- Diego Linares Castillo. (diegojeanluck@hotmail.com)
- Luis Manrique Chávez. (luismanrique158158@gmail.com)