find_the_difference_of_two_arrays.py

'''
2215. Find the Difference of Two Arrays
Solved
Easy
Topics
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Hint

Given two 0-indexed integer arrays nums1 and nums2, return a list answer of size 2 where:
    answer[0] is a list of all distinct integers in nums1 which are not present in nums2.
    answer[1] is a list of all distinct integers in nums2 which are not present in nums1.
Note that the integers in the lists may be returned in any order.
 
Example 1:
Input: nums1 = [1,2,3], nums2 = [2,4,6]
Output: [[1,3],[4,6]]
Explanation:
For nums1, nums1[1] = 2 is present at index 0 of nums2, whereas nums1[0] = 1 and nums1[2] = 3 are not present in nums2. Therefore, answer[0] = [1,3].
For nums2, nums2[0] = 2 is present at index 1 of nums1, whereas nums2[1] = 4 and nums2[2] = 6 are not present in nums2. Therefore, answer[1] = [4,6].

Example 2:
Input: nums1 = [1,2,3,3], nums2 = [1,1,2,2]
Output: [[3],[]]
Explanation:
For nums1, nums1[2] and nums1[3] are not present in nums2. Since nums1[2] == nums1[3], their value is only included once and answer[0] = [3].
Every integer in nums2 is present in nums1. Therefore, answer[1] = [].

Constraints:
    1 <= nums1.length, nums2.length <= 1000
    -1000 <= nums1[i], nums2[i] <= 1000
'''

class Solution:
    def findDifference(self, nums1: List[int], nums2: List[int]) -> List[List[int]]:
        new_list = [[],[]]
        for i in nums1:
            if i not in nums2:
                if i not in new_list[0]:
                    new_list[0].append(i)
        for i in nums2:
            if i not in nums1:
                if i not in new_list[1]:
                    new_list[1].append(i)
        return new_list